Упр.605 Часть 2 ГДЗ Виленкин Жохов 6 класс (Математика)

а) (156,6 : 18 — 8,6) * 100 : 0,1 — 99;
б) 11,21 — (38,418 : 0,3 — 4,8 * 11,6) : 11 + 13,79;
в) (2,727 : (-0,9) + 1,9 * (-5,3) + 1,58) : 4,8;
г) 4,2 * (-0,3) : 0,9 — 5,6 : (-1,4) * 3,7;
д) -11/13 : (-1 9/13) + 5,52 : (-13,8) — 0,1;
е) (7 — 4 3/4) * 1 1/3 + (6 — 4 2/5) : 1 1/3;
ж) 10 — 3 3/4 * (2 1/3 + 1 2/5) : 1 5/9;
з) 7 1/2 : 2 1/2 * 3 2/3 — 5 1/5 * 5/13 * (1 1/2)3;
и) -3/14 * 7/9 — 8/15 : (-4/5) + 1/12;
к) 8/9 * (2 1/4)2 — 3/7 : 3 3/7 + 5/6 : 3 1/3.

а) $$\left(156{,}6:18-8{,}6\right)\cdot 100:0{,}1-99$$

$$156{,}6:18=8{,}7$$
$$8{,}7-8{,}6=0{,}1$$
$$0{,}1\cdot 100:0{,}1-99=10:0{,}1-99=100-99=1$$

б) $$11{,}21-\left(38{,}418:0{,}3-4{,}8\cdot 11{,}6\right):11+13{,}79$$

$$38{,}418:0{,}3=128{,}06$$
$$4{,}8\cdot 11{,}6=55{,}68$$
$$128{,}06-55{,}68=72{,}38$$
$$72{,}38:11=6{,}58$$
$$11{,}21-6{,}58+13{,}79=4{,}63+13{,}79=18{,}42$$

в) $$\left(2{,}727:(-0{,}9)+1{,}9\cdot(-5{,}3)+1{,}58\right):4{,}8$$

$$2{,}727:(-0{,}9)=-3{,}03$$
$$1{,}9\cdot(-5{,}3)=-10{,}07$$
$$-3{,}03-10{,}07+1{,}58=-11{,}52$$
$$-11{,}52:4{,}8=-2{,}4$$

г) $$4{,}2\cdot(-0{,}3):0{,}9-5{,}6:(-1{,}4)\cdot 3{,}7$$

$$4{,}2\cdot(-0{,}3)=-1{,}26$$
$$-1{,}26:0{,}9=-1{,}4$$
$$5{,}6:(-1{,}4)=-4$$
$$-4\cdot 3{,}7=-14{,}8$$
$$-1{,}4-(-14{,}8)=13{,}4$$

д) $$-\frac{11}{13}:(-1\frac{9}{13})+5{,}52:(-13{,}8)-0{,}1$$

$$-1\frac{9}{13}=-\frac{22}{13}, \quad 5{,}52:(-13{,}8)=-0{,}4$$
$$-\frac{11}{13}:\left(-\frac{22}{13}\right)=\frac{11}{22}=\frac{1}{2}$$
$$\frac{1}{2}-0{,}4-0{,}1=\frac{1}{2}-\frac{1}{2}=0$$

е) $$\left(7-4\frac{3}{4}\right)\cdot 1\frac{1}{3}+\left(6-4\frac{2}{5}\right):1\frac{1}{3}$$

$$7-4\frac{3}{4}=2\frac{1}{4}, \quad 6-4\frac{2}{5}=1\frac{3}{5}$$
$$2\frac{1}{4}\cdot 1\frac{1}{3}=\frac{9}{4}\cdot\frac{4}{3}=3$$
$$1\frac{3}{5}:1\frac{1}{3}=\frac{8}{5}:\frac{4}{3}=\frac{8}{5}\cdot\frac{3}{4}=\frac{6}{5}$$
$$3+\frac{6}{5}=4\frac{1}{5}=4{,}2$$

ж) $$10-3\frac{3}{4}\cdot\left(2\frac{1}{3}+1\frac{2}{5}\right):1\frac{5}{9}$$

$$2\frac{1}{3}+1\frac{2}{5}=\frac{7}{3}+\frac{7}{5}=\frac{56}{15}$$
$$3\frac{3}{4}\cdot\frac{56}{15}:1\frac{5}{9}=\frac{15}{4}\cdot\frac{56}{15}:\frac{14}{9}$$
$$=\frac{56}{4}\cdot\frac{9}{14}=14\cdot\frac{9}{14}=9$$
$$10-9=1$$

з) $$7\frac{1}{2}:2\frac{1}{2}\cdot 3\frac{2}{3}-5\frac{1}{5}\cdot\frac{5}{13}\cdot\left(1\frac{1}{2}\right)^3$$

$$7\frac{1}{2}:2\frac{1}{2}\cdot 3\frac{2}{3}=\frac{15}{2}:\frac{5}{2}\cdot\frac{11}{3}=3\cdot\frac{11}{3}=11$$
$$5\frac{1}{5}\cdot\frac{5}{13}\cdot\left(1\frac{1}{2}\right)^3=\frac{26}{5}\cdot\frac{5}{13}\cdot\left(\frac{3}{2}\right)^3=2\cdot\frac{27}{8}=\frac{27}{4}$$
$$11-\frac{27}{4}=6\frac{1}{4}$$

и) $$-\frac{3}{14}\cdot\frac{7}{9}-\frac{8}{15}:(-\frac{4}{5})+\frac{1}{12}$$

$$-\frac{3}{14}\cdot\frac{7}{9}=-\frac{1}{6}$$
$$\frac{8}{15}:(-\frac{4}{5})=-\frac{2}{3}$$
$$-\frac{1}{6}-\left(-\frac{2}{3}\right)+\frac{1}{12}=-\frac{1}{6}+\frac{2}{3}+\frac{1}{12}$$
$$-\frac{1}{6}+\frac{2}{3}+\frac{1}{12}=-\frac{2}{12}+\frac{8}{12}+\frac{1}{12}=\frac{7}{12}$$

к) $$\frac{8}{9}\cdot\left(2\frac{1}{4}\right)^2-\frac{3}{7}:3\frac{3}{7}+\frac{5}{6}:3\frac{1}{3}$$

$$\left(2\frac{1}{4}\right)^2=\left(\frac{9}{4}\right)^2=\frac{81}{16}$$
$$\frac{8}{9}\cdot\frac{81}{16}=\frac{9}{2}$$
$$\frac{3}{7}:3\frac{3}{7}=\frac{3}{7}:\frac{24}{7}=\frac{1}{8}$$
$$\frac{5}{6}:3\frac{1}{3}=\frac{5}{6}:\frac{10}{3}=\frac{1}{4}$$
$$\frac{9}{2}-\frac{1}{8}+\frac{1}{4}=4\frac{5}{8}$$

Ответ

а) $$1$$; б) $$18{,}42$$; в) $$-2{,}4$$; г) $$13{,}4$$; д) $$0$$; е) $$4{,}2$$; ж) $$1$$; з) $$6\frac{1}{4}$$; и) $$\frac{7}{12}$$; к) $$4\frac{5}{8}$$.