Задачи на повторение П.17 ГДЗ Виленкин Жохов 6 класс Часть 2, Просвещение (Математика)
а) -17/17 : (-1 7/17) + 5,88 : (-14,7) — 0,1; г) 2 4/5 : 1 2/5 · 5 1/2 — 4 2/7 · 7/15 · (1 1/2)^3;
б) (8 — 5 3/4) · 2 2/3 + (8 — 6 3/5) : 1 3/4; д) -5/8 · 4/15 — 14/33 : (-7/11) + 1/12;
в) 5,5 — 3 3/4 · (1 2/3 + 1 2/5) : 2 5/9; е) 2/7 · (3 1/2)^2 — 5/13 : 3 1/13 + 9/10 : 3 3/5.
а) $$-\frac{12}{17} : \left(-1\frac{7}{17}\right) + 5{,}88 : (-14{,}7) — 0{,}1$$
$$-\frac{12}{17} : \left(-\frac{24}{17}\right) + \frac{588}{100} : \left(-\frac{147}{10}\right) — \frac{1}{10}$$
$$\frac{12}{17}\cdot\frac{17}{24} — 0{,}4 — 0{,}1 = \frac{1}{2} — 0{,}4 — 0{,}1 = 0$$
б) $$\left(8-5\frac{3}{4}\right)\cdot 2\frac{2}{3} + \left(8-6\frac{3}{5}\right):1\frac{3}{4}$$
$$\left(8-\frac{23}{4}\right)\cdot\frac{8}{3} + \left(8-\frac{33}{5}\right):\frac{7}{4}$$
$$\frac{9}{4}\cdot\frac{8}{3} + \frac{7}{5}:\frac{7}{4} = 6 + \frac{4}{5} = 6{,}8$$
в) $$5{,}5 — 3\frac{3}{4}\cdot\left(1\frac{2}{3}+1\frac{2}{5}\right):2\frac{5}{9}$$
$$5{,}5 — \frac{15}{4}\cdot\left(\frac{5}{3}+\frac{7}{5}\right):\frac{23}{9}$$
$$5{,}5 — \frac{15}{4}\cdot\frac{46}{15}\cdot\frac{9}{23} = 5{,}5 — 4{,}5 = 1$$
г) $$2\frac{4}{5}:1\frac{2}{5}\cdot 5\frac{1}{2} — 4\frac{2}{7}\cdot\frac{7}{15}\cdot\left(1\frac{1}{2}\right)^3$$
$$\frac{14}{5}:\frac{7}{5}\cdot\frac{11}{2} — \frac{30}{7}\cdot\frac{7}{15}\cdot\left(\frac{3}{2}\right)^3$$
$$2\cdot\frac{11}{2} — 2\cdot\frac{27}{8} = 11 — \frac{27}{4} = \frac{17}{4} = 4\frac{1}{4}$$
д) $$-\frac{5}{8}\cdot\frac{4}{15} — \frac{14}{33}:\left(-\frac{7}{11}\right) + \frac{1}{12}$$
$$-\frac{1}{6} + \frac{2}{3} + \frac{1}{12}$$
$$-\frac{2}{12} + \frac{8}{12} + \frac{1}{12} = \frac{7}{12}$$
е) $$\frac{2}{7}\cdot\left(3\frac{1}{2}\right)^2 — \frac{5}{13}:3\frac{1}{13} + \frac{9}{10}:3\frac{3}{5}$$
$$\frac{2}{7}\cdot\left(\frac{7}{2}\right)^2 — \frac{5}{13}:\frac{40}{13} + \frac{9}{10}:\frac{18}{5}$$
$$\frac{2}{7}\cdot\frac{49}{4} — \frac{1}{8} + \frac{1}{4} = \frac{7}{2} — \frac{1}{8} + \frac{1}{4} = \frac{29}{8} = 3\frac{5}{8}$$
Ответ
а) $$0$$; б) $$6{,}8$$; в) $$1$$; г) $$4\frac{1}{4}$$; д) $$\frac{7}{12}$$; е) $$3\frac{5}{8}$$.