Упр.723 ГДЗ Ткачёва 6 класс (Математика)

1) -128,52 : 6,3; 2) 8,289 : (-0,27); 3) -1 11/49 : (-1 6/7); 4) -1 13/35 : (-3 3/5).

1) $$-128{,}52 : 6{,}3 = -1285{,}2 : 63 = -20{,}4$$

Проверка:

$$-128{,}52 : (-20{,}4) = 1285{,}2 : 204 = 6{,}3$$

2) $$8{,}289 : (-0{,}27) = -828{,}9 : 27 = -30{,}7$$

Проверка:

$$8{,}289 : (-30{,}7) = -82{,}89 : 307 = -0{,}27$$

3) $$-1\frac{11}{49} : \left(-1\frac{6}{7}\right) = \frac{60}{49} : \frac{13}{7} = \frac{60}{49}\cdot\frac{7}{13} = \frac{60\cdot 7}{49\cdot 13} = \frac{60}{91}$$

Проверка:

$$-1\frac{11}{49} : \frac{60}{91} = -\frac{60}{49}\cdot\frac{91}{60} = -\frac{91}{49} = -\frac{13}{7} = -1\frac{6}{7}$$

4) $$-1\frac{13}{35} : \left(-3\frac{3}{5}\right) = \frac{48}{35} : \frac{18}{5} = \frac{48}{35}\cdot\frac{5}{18} = \frac{48\cdot 5}{35\cdot 18} = \frac{8}{21}$$

Проверка:

$$-1\frac{13}{35} : \frac{8}{21} = -\frac{48}{35}\cdot\frac{21}{8} = -\frac{6\cdot 3}{5\cdot 1} = -\frac{18}{5} = -3\frac{3}{5}$$

Ответ

1) $$-20{,}4$$; 2) $$-30{,}7$$; 3) $$\frac{60}{91}$$; 4) $$\frac{8}{21}$$.