Упр.113 ГДЗ Ткачёва 6 класс (Математика)

Вычислить:
1) $$7\frac{5}{8}+3\frac{2}{9}-6\frac{5}{8}$$;
2) $$5\frac{1}{23}+2\frac{3}{8}-3\frac{1}{23}$$;
3) $$4\frac{8}{21}+1\frac{1}{6}\cdot\frac{6}{7}$$;
3) $$8\frac{1}{6}-\left(2\frac{5}{11}+5\frac{1}{6}\right)$$.

1) $$7\frac{5}{8}+3\frac{2}{9}-6\frac{5}{8}=\left(7\frac{5}{8}-6\frac{5}{8}\right)+3\frac{2}{9}=1+3\frac{2}{9}=4\frac{2}{9}.$$

2) $$5\frac{1}{23}+2\frac{3}{8}-3\frac{1}{23}=\left(5\frac{1}{23}-3\frac{1}{23}\right)+2\frac{3}{8}=2+2\frac{3}{8}=4\frac{3}{8}.$$

3) $$4\frac{8}{21}+1\frac{1}{6}\cdot\frac{6}{7}=4\frac{8}{21}+\frac{7}{6}\cdot\frac{6}{7}=4\frac{8}{21}+1=5\frac{8}{21}.$$

4) $$8\frac{1}{6}-\left(2\frac{5}{11}+5\frac{1}{6}\right)=\left(8\frac{1}{6}-5\frac{1}{6}\right)-2\frac{5}{11}=3-2\frac{5}{11}=1\frac{6}{11}.$$

Ответ

1) $$4\frac{2}{9}$$; 2) $$4\frac{3}{8}$$; 3) $$5\frac{8}{21}$$; 4) $$1\frac{6}{11}$$.