Упр.313 ГДЗ Муравин 6 класс (Математика)

1) 10/18+24 36/81;
2) 7 33/87-6 22/58;
3) 5 4/9•2 11/98;
4) 8 12/31•9 7/13;
5) 4 4/5 :4/17 :3 2/5;
6) 11 1/3 :4/21 :4 1/4;
7) 1 2/7•1 1/4•4/9•2 3/4;
8) 2 11/50 :7 2/5•3 1/3.

1) $$\frac{10}{18}+24\frac{36}{81}=\frac{5}{9}+24\frac{4}{9}=24+\frac{5}{9}+\frac{4}{9}=24+1=25.$$

2) $$7\frac{33}{87}-6\frac{22}{58}=7\frac{11}{29}-6\frac{11}{29}=1.$$

3) $$5\frac{4}{9}\cdot 2\frac{11}{98}=\frac{49}{9}\cdot\frac{207}{98}=\frac{1}{9}\cdot\frac{23}{2}=\frac{23}{2}=11\frac{1}{2}.$$

4) $$8\frac{12}{31}\cdot 9\frac{7}{13}=\frac{260}{31}\cdot\frac{124}{13}=\frac{20}{1}\cdot\frac{4}{1}=80.$$

5) $$4\frac{4}{5}:\frac{4}{17}:3\frac{2}{5}=\frac{24}{5}:\frac{4}{17}:\frac{17}{5}=\frac{24}{5}\cdot\frac{17}{4}\cdot\frac{5}{17}=6.$$

6) $$11\frac{1}{3}:\frac{4}{21}:4\frac{1}{4}=\frac{34}{3}:\frac{4}{21}:\frac{17}{4}=\frac{34}{3}\cdot\frac{21}{4}\cdot\frac{4}{17}=14.$$

7) $$1\frac{2}{7}\cdot 1\frac{1}{4}\cdot\frac{4}{9}\cdot 2\frac{3}{4}=\frac{9}{7}\cdot\frac{5}{4}\cdot\frac{4}{9}\cdot\frac{11}{4}=\frac{55}{28}=1\frac{27}{28}.$$

8) $$2\frac{11}{50}:7\frac{2}{5}\cdot 3\frac{1}{3}=\frac{111}{50}:\frac{37}{5}\cdot\frac{10}{3}=\frac{111}{50}\cdot\frac{5}{37}\cdot\frac{10}{3}=1.$$

Ответ

1) $$25$$; 2) $$1$$; 3) $$11\frac{1}{2}$$; 4) $$80$$; 5) $$6$$; 6) $$14$$; 7) $$1\frac{27}{28}$$; 8) $$1$$.