Упр.1352 ГДЗ Мерзляк Полонский 6 класс (Математика)

a = (-3,8) — (-4,3)) : (-1*1/3);
b = (5*7/8 — 6*1/12): 1*7/18;
c = (-1*5/8 — (-2,15)): (-2*4/5);
d = (-1*5/12 — 1*2/15)*(-5/17)?

Вычислим значения чисел:

$$ a=(-3{,}8-(-4{,}3)):(-1\tfrac{1}{3})=( -3{,}8+4{,}3):\left(-\tfrac{4}{3}\right)=0{,}5\cdot\left(-\tfrac{3}{4}\right)=-\tfrac{3}{8}=-0{,}375 $$

$$ b=\left(5\tfrac{7}{8}-6\tfrac{1}{12}\right):1\tfrac{7}{18} =\left(5\tfrac{21}{24}-6\tfrac{2}{24}\right):\tfrac{25}{18} =-\tfrac{5}{24}\cdot\tfrac{18}{25} =-\tfrac{3}{20}=-0{,}15 $$

$$ c=\left(-1\tfrac{5}{8}-(-2{,}15)\right):\left(-2\tfrac{4}{5}\right) =\left(-1\tfrac{5}{8}+2\tfrac{15}{100}\right):\left(-\tfrac{14}{5}\right) $$
$$ =\left(-1\tfrac{25}{40}+2\tfrac{6}{40}\right):\left(-\tfrac{14}{5}\right) =\tfrac{21}{40}\cdot\left(-\tfrac{5}{14}\right) =-\tfrac{3}{16}=-0{,}1875 $$

$$ d=\left(-1\tfrac{5}{12}-1\tfrac{2}{15}\right)\cdot\left(-\tfrac{5}{17}\right) =\left(-1\tfrac{25}{60}-1\tfrac{8}{60}\right)\cdot\left(-\tfrac{5}{17}\right) =-2\tfrac{33}{60}\cdot\left(-\tfrac{5}{17}\right) $$
$$ =2\tfrac{11}{20}\cdot\tfrac{5}{17} =\tfrac{51}{20}\cdot\tfrac{5}{17} =\tfrac{3}{4}=0{,}75 $$

Теперь сравним модули:

$$ |a|=0{,}375,\quad |b|=0{,}15,\quad |c|=0{,}1875,\quad |d|=0{,}75 $$

Наибольший модуль у числа $$d$$.

Ответ: $$d,\ 0{,}75$$.