Упр.15.15 ГДЗ Рабочая тетрадь Зубарева Мордкович 6 класс Экзамен (Математика)

а) 16 8/9 :8; 34 4/9 :2; 35 5/8 :5;
б) 120 6/7 :3; 14 7/3 :7; 26 8/11 :2;
в) 64 16/21 :4; 38 6/11 :2; 100 50/109 :25;
г) 49 14/15 :7; 84 42/271 :42; 100 75/647 :25.

Используем правило: чтобы разделить смешанное число на натуральное число, можно разделить отдельно целую часть и дробную часть.

а)

$$16\frac{8}{9}:8=16:8+\frac{8}{9}:8=2+\frac{8}{9}\cdot\frac{1}{8}=2+\frac{1}{9}=2\frac{1}{9}$$

$$34\frac{4}{9}:2=34:2+\frac{4}{9}:2=17+\frac{4}{9}\cdot\frac{1}{2}=17+\frac{2}{9}=17\frac{2}{9}$$

$$35\frac{5}{8}:5=35:5+\frac{5}{8}:5=7+\frac{5}{8}\cdot\frac{1}{5}=7+\frac{1}{8}=7\frac{1}{8}$$

б)

$$120\frac{6}{7}:3=120:3+\frac{6}{7}:3=40+\frac{6}{7}\cdot\frac{1}{3}=40+\frac{2}{7}=40\frac{2}{7}$$

$$14\frac{7}{3}:7=14:7+\frac{7}{3}:7=2+\frac{7}{3}\cdot\frac{1}{7}=2+\frac{1}{3}=2\frac{1}{3}$$

$$26\frac{8}{11}:2=26:2+\frac{8}{11}:2=13+\frac{8}{11}\cdot\frac{1}{2}=13+\frac{4}{11}=13\frac{4}{11}$$

в)

$$64\frac{16}{21}:4=64:4+\frac{16}{21}:4=16+\frac{16}{21}\cdot\frac{1}{4}=16+\frac{4}{21}=16\frac{4}{21}$$

$$38\frac{6}{11}:2=38:2+\frac{6}{11}:2=19+\frac{6}{11}\cdot\frac{1}{2}=19+\frac{3}{11}=19\frac{3}{11}$$

$$100\frac{50}{109}:25=100:25+\frac{50}{109}:25=4+\frac{50}{109}\cdot\frac{1}{25}=4+\frac{2}{109}=4\frac{2}{109}$$

г)

$$49\frac{14}{15}:7=49:7+\frac{14}{15}:7=7+\frac{14}{15}\cdot\frac{1}{7}=7+\frac{2}{15}=7\frac{2}{15}$$

$$84\frac{42}{271}:42=84:42+\frac{42}{271}:42=2+\frac{42}{271}\cdot\frac{1}{42}=2+\frac{1}{271}=2\frac{1}{271}$$

$$100\frac{75}{647}:25=100:25+\frac{75}{647}:25=4+\frac{75}{647}\cdot\frac{1}{25}=4+\frac{3}{647}=4\frac{3}{647}$$

Ответ

а) $$2\frac{1}{9};\ 17\frac{2}{9};\ 7\frac{1}{8}$$

б) $$40\frac{2}{7};\ 2\frac{1}{3};\ 13\frac{4}{11}$$

в) $$16\frac{4}{21};\ 19\frac{3}{11};\ 4\frac{2}{109}$$

г) $$7\frac{2}{15};\ 2\frac{1}{271};\ 4\frac{3}{647}$$