Упр.1.10 ГДЗ Рабочая тетрадь Зубарева 6 класс Мнемозина (Математика)

Начнём вычисления с верхнего кружка и продолжим по часовой стрелке.

а)

$$\frac{3}{4}:3=\frac{3}{4}\cdot\frac{1}{3}=\frac{1}{4}$$
$$\frac{3}{4}-\frac{1}{4}=\frac{2}{4}=\frac{1}{2}$$
$$\frac{3}{4}-\frac{1}{2}=\frac{3}{4}-\frac{2}{4}=\frac{1}{4}$$
$$\frac{3}{4}\cdot 3=\frac{9}{4}=2\frac{1}{4}$$
$$\frac{3}{4}+\frac{1}{2}=\frac{3}{4}+\frac{2}{4}=\frac{5}{4}=1\frac{1}{4}$$
$$\frac{3}{4}+\frac{1}{4}=1$$

б)

$$\frac{9}{14}\cdot 2=\frac{9}{7}=1\frac{2}{7}$$
$$\frac{9}{14}+\frac{1}{7}=\frac{9}{14}+\frac{2}{14}=\frac{11}{14}$$
$$\frac{9}{14}-\frac{1}{14}=\frac{8}{14}=\frac{4}{7}$$
$$\frac{9}{14}:2=\frac{9}{14}\cdot\frac{1}{2}=\frac{9}{28}$$
$$\frac{9}{14}-\frac{1}{7}=\frac{9}{14}-\frac{2}{14}=\frac{7}{14}=\frac{1}{2}$$
$$\frac{9}{14}+\frac{1}{14}=\frac{10}{14}=\frac{5}{7}$$

в)

$$\frac{4}{5}:2=\frac{4}{5}\cdot\frac{1}{2}=\frac{2}{5}$$
$$\frac{4}{5}+\frac{1}{10}=\frac{8}{10}+\frac{1}{10}=\frac{9}{10}$$
$$\frac{4}{5}\cdot 2=\frac{8}{5}=1\frac{3}{5}$$
$$\frac{4}{5}:3=\frac{4}{5}\cdot\frac{1}{3}=\frac{4}{15}$$
$$\frac{4}{5}-\frac{1}{15}=\frac{12}{15}-\frac{1}{15}=\frac{11}{15}$$
$$\frac{4}{5}\cdot 3=\frac{12}{5}=2\frac{2}{5}$$

г)

$$\frac{4}{9}:2=\frac{4}{9}\cdot\frac{1}{2}=\frac{2}{9}$$
$$\frac{4}{9}\cdot 3=\frac{4}{3}=1\frac{1}{3}$$
$$\frac{4}{9}+\frac{1}{3}=\frac{4}{9}+\frac{3}{9}=\frac{7}{9}$$
$$\frac{4}{9}:3=\frac{4}{9}\cdot\frac{1}{3}=\frac{4}{27}$$
$$\frac{4}{9}\cdot 2=\frac{8}{9}$$
$$\frac{4}{9}-\frac{1}{3}=\frac{4}{9}-\frac{3}{9}=\frac{1}{9}$$

Ответ: а) $$\frac14,\ \frac12,\ \frac14,\ 2\frac14,\ 1\frac14,\ 1$$; б) $$1\frac27,\ \frac{11}{14},\ \frac47,\ \frac{9}{28},\ \frac12,\ \frac57$$; в) $$\frac25,\ \frac9{10},\ 1\frac35,\ \frac4{15},\ \frac{11}{15},\ 2\frac25$$; г) $$\frac29,\ 1\frac13,\ \frac79,\ \frac4{27},\ \frac89,\ \frac19$$.