Упр.876 ГДЗ Ткачёва 5 класс (Математика)
- Вычислить:
1) $$12\frac{3}{7}-5\frac{2}{7}$$;
2) $$10\frac{2}{5}-6\frac{1}{5}$$;
3) $$4-\frac{3}{8}$$;
4) $$7-\frac{9}{14}$$;
5) $$5\frac{1}{4}-\frac{3}{4}$$;
6) $$6\frac{2}{7}-\frac{5}{7}$$;
7) $$3\frac{2}{5}-1\frac{3}{5}$$;
8) $$4\frac{1}{6}-1\frac{5}{6}$$;
9) $$9\frac{3}{13}-8\frac{9}{13}$$;
10) $$7\frac{4}{17}-6\frac{11}{17}$$.
1) $$12\frac{3}{7}-5\frac{2}{7}=(12-5)+\left(\frac{3}{7}-\frac{2}{7}\right)=7+\frac{1}{7}=7\frac{1}{7}$$
2) $$10\frac{2}{5}-6\frac{1}{5}=(10-6)+\left(\frac{2}{5}-\frac{1}{5}\right)=4+\frac{1}{5}=4\frac{1}{5}$$
3) $$4-\frac{3}{8}=\left(3+\frac{8}{8}\right)-\frac{3}{8}=3+\left(\frac{8}{8}-\frac{3}{8}\right)=3+\frac{5}{8}=3\frac{5}{8}$$
4) $$7-\frac{9}{14}=\left(6+\frac{14}{14}\right)-\frac{9}{14}=6+\left(\frac{14}{14}-\frac{9}{14}\right)=6+\frac{5}{14}=6\frac{5}{14}$$
5) $$5\frac{1}{4}-\frac{3}{4}=4\frac{5}{4}-\frac{3}{4}=4+\left(\frac{5}{4}-\frac{3}{4}\right)=4+\frac{2}{4}=4\frac{1}{2}$$
6) $$6\frac{2}{7}-\frac{5}{7}=5\frac{9}{7}-\frac{5}{7}=5+\left(\frac{9}{7}-\frac{5}{7}\right)=5+\frac{4}{7}=5\frac{4}{7}$$
7) $$3\frac{2}{5}-1\frac{3}{5}=2\frac{7}{5}-1\frac{3}{5}=2+\frac{7}{5}-\left(1+\frac{3}{5}\right)=(2-1)+\left(\frac{7}{5}-\frac{3}{5}\right)=1+\frac{4}{5}=1\frac{4}{5}$$
8) $$4\frac{1}{6}-1\frac{5}{6}=3\frac{7}{6}-1\frac{5}{6}=3+\frac{7}{6}-\left(1+\frac{5}{6}\right)=(3-1)+\left(\frac{7}{6}-\frac{5}{6}\right)=2+\frac{2}{6}=2\frac{1}{3}$$
9) $$9\frac{3}{13}-8\frac{9}{13}=8\frac{16}{13}-8\frac{9}{13}=8+\frac{16}{13}-\left(8+\frac{9}{13}\right)=(8-8)+\left(\frac{16}{13}-\frac{9}{13}\right)=\frac{7}{13}$$
10) $$7\frac{4}{17}-6\frac{11}{17}=6\frac{21}{17}-6\frac{11}{17}=6+\frac{21}{17}-\left(6+\frac{11}{17}\right)=(6-6)+\left(\frac{21}{17}-\frac{11}{17}\right)=\frac{10}{17}$$
Ответ
1) $$7\frac{1}{7}$$; 2) $$4\frac{1}{5}$$; 3) $$3\frac{5}{8}$$; 4) $$6\frac{5}{14}$$; 5) $$4\frac{1}{2}$$; 6) $$5\frac{4}{7}$$; 7) $$1\frac{4}{5}$$; 8) $$2\frac{1}{3}$$; 9) $$\frac{7}{13}$$; 10) $$\frac{10}{17}$$.












