Упр.1058 ГДЗ Мерзляк Полонский 5 класс (Математика)

1) $$\left(\frac{11}{18}-\frac{4}{9}\right)\cdot\frac{3}{16}=\left(\frac{11}{18}-\frac{8}{18}\right)\cdot\frac{3}{16}=\frac{3}{18}\cdot\frac{3}{16}=\frac{1}{6}\cdot\frac{3}{16}=\frac{1}{32}.$$

2) $$\frac{11}{18}-\frac{4}{9}\cdot\frac{3}{16}=\frac{11}{18}-\frac{4\cdot 3}{9\cdot 16}=\frac{11}{18}-\frac{1}{12}=\frac{22}{36}-\frac{3}{36}=\frac{19}{36}.$$

3) $$1\frac{3}{5}\cdot\left(\frac{3}{4}+1\frac{3}{8}\right)=\frac{8}{5}\cdot\left(\frac{6}{8}+\frac{11}{8}\right)=\frac{8}{5}\cdot\frac{17}{8}=\frac{17}{5}=3\frac{2}{5}.$$

4) $$1\frac{3}{5}\cdot\frac{3}{4}+1\frac{3}{8}=\frac{8}{5}\cdot\frac{3}{4}+\frac{11}{8}=\frac{6}{5}+\frac{11}{8}=\frac{48}{40}+\frac{55}{40}=\frac{103}{40}=2\frac{23}{40}.$$

5) $$1\frac{3}{25}\cdot 2\frac{1}{7}-2\frac{1}{9}\cdot\frac{27}{190}=\frac{28}{25}\cdot\frac{15}{7}-\frac{19}{9}\cdot\frac{27}{190}=\frac{4\cdot 3}{5}-\frac{3}{10}=\frac{12}{5}-\frac{3}{10}=\frac{24}{10}-\frac{3}{10}=\frac{21}{10}=2\frac{1}{10}.$$

6) $$\left(8-2\frac{1}{7}\cdot 3\frac{1}{9}\right)\cdot\frac{27}{44}=\left(8-\frac{15}{7}\cdot\frac{28}{9}\right)\cdot\frac{27}{44}=\left(8-\frac{20}{3}\right)\cdot\frac{27}{44}=\left(\frac{24}{3}-\frac{20}{3}\right)\cdot\frac{27}{44}=\frac{4}{3}\cdot\frac{27}{44}=\frac{9}{11}.$$

Мировой океан занимает $$100\%-29\%=71\%.$$

Ответ

1) $$\frac{1}{32}$$; 2) $$\frac{19}{36}$$; 3) $$3\frac{2}{5}$$; 4) $$2\frac{23}{40}$$; 5) $$2\frac{1}{10}$$; 6) $$\frac{9}{11}$$; $$71\%$$.