Упр.397 Часть 2 ГДЗ Дорофеев Петерсон 5 класс (Математика)

Рассмотрим вариант решения задания из учебника Дорофеев, Петерсон 5 класс, Бином: 397. Придумай 100 несократимых дробей и расположи их в возрастающем порядке.

Можно взять, например, такие 100 несократимых дробей:

$$\frac12,\ \frac23,\ \frac34,\ \frac45,\ \frac56,\ \frac67,\ \frac78,\ \frac89,\ \frac9{10},\ \frac{10}{11},$$
$$\frac{11}{12},\ \frac{12}{13},\ \frac{13}{14},\ \frac{14}{15},\ \frac{15}{16},\ \frac{16}{17},\ \frac{17}{18},\ \frac{18}{19},\ \frac{19}{20},\ \frac{20}{21},$$
$$\frac{21}{22},\ \frac{22}{23},\ \frac{23}{24},\ \frac{24}{25},\ \frac{25}{26},\ \frac{26}{27},\ \frac{27}{28},\ \frac{28}{29},\ \frac{29}{30},\ \frac{30}{31},$$
$$\frac{31}{32},\ \frac{32}{33},\ \frac{33}{34},\ \frac{34}{35},\ \frac{35}{36},\ \frac{36}{37},\ \frac{37}{38},\ \frac{38}{39},\ \frac{39}{40},\ \frac{40}{41},$$
$$\frac{41}{42},\ \frac{42}{43},\ \frac{43}{44},\ \frac{44}{45},\ \frac{45}{46},\ \frac{46}{47},\ \frac{47}{48},\ \frac{48}{49},\ \frac{49}{50},\ \frac{50}{51},$$
$$\frac{51}{52},\ \frac{52}{53},\ \frac{53}{54},\ \frac{54}{55},\ \frac{55}{56},\ \frac{56}{57},\ \frac{57}{58},\ \frac{58}{59},\ \frac{59}{60},\ \frac{60}{61},$$
$$\frac{61}{62},\ \frac{62}{63},\ \frac{63}{64},\ \frac{64}{65},\ \frac{65}{66},\ \frac{66}{67},\ \frac{67}{68},\ \frac{68}{69},\ \frac{69}{70},\ \frac{70}{71},$$
$$\frac{71}{72},\ \frac{72}{73},\ \frac{73}{74},\ \frac{74}{75},\ \frac{75}{76},\ \frac{76}{77},\ \frac{77}{78},\ \frac{78}{79},\ \frac{79}{80},\ \frac{80}{81},$$
$$\frac{81}{82},\ \frac{82}{83},\ \frac{83}{84},\ \frac{84}{85},\ \frac{85}{86},\ \frac{86}{87},\ \frac{87}{88},\ \frac{88}{89},\ \frac{89}{90},\ \frac{90}{91},$$
$$\frac{91}{92},\ \frac{92}{93},\ \frac{93}{94},\ \frac{94}{95},\ \frac{95}{96},\ \frac{96}{97},\ \frac{97}{98},\ \frac{98}{99},\ \frac{99}{100},\ \frac{100}{101}.$$

Ответ: $$\frac12,\ \frac23,\ \frac34,\ \frac45,\ \frac56,\ \frac67,\ \frac78,\ \frac89,\ \frac9{10},\ \frac{10}{11},\ \ldots,\ \frac{100}{101}.$$