Упр.18 Параграф 14 Часть 2 ГДЗ Рудницкая Юдачева 4 класс (2023) (Математика)

Задача

1 070 + 86 · 101 — 2 008 — 2 116 : 46
123 · 60 + 1 356 : 12 + 5 041 : 71 · 15 · 5
190 · 50 — 3 283 : 49 + 69 046 : 23
2 491 : 47 + 8 364 : 82 — 3 094 : 91

Подробный ответ

1) $$1\,070 + 86 \cdot 101 — 2\,008 — 2\,116 : 46$$

$$86 \cdot 101 = 8\,686$$

$$2\,116 : 46 = 46$$

$$1\,070 + 8\,686 = 9\,756$$

$$9\,756 — 2\,008 = 7\,748$$

$$7\,748 — 46 = 7\,702$$

Получаем: $$7\,702$$.

2) $$123 \cdot 60 + 1\,356 : 12 + 5\,041 : 71 \cdot 15 \cdot 5$$

$$123 \cdot 60 = 7\,380$$

$$1\,356 : 12 = 113$$

$$5\,041 : 71 = 71$$

$$71 \cdot 15 = 1\,065$$

$$1\,065 \cdot 5 = 5\,325$$

$$7\,380 + 113 = 7\,493$$

$$7\,493 + 5\,325 = 12\,818$$

Получаем: $$12\,818$$.

3) $$190 \cdot 50 — 3\,283 : 49 + 69\,046 : 23$$

$$190 \cdot 50 = 9\,500$$

$$3\,283 : 49 = 67$$

$$69\,046 : 23 = 3\,002$$

$$9\,500 — 67 = 9\,433$$

$$9\,433 + 3\,002 = 12\,435$$

Получаем: $$12\,435$$.

4) $$2\,491 : 47 + 8\,364 : 82 — 3\,094 : 91$$

$$2\,491 : 47 = 53$$

$$8\,364 : 82 = 102$$

$$3\,094 : 91 = 34$$

$$53 + 102 = 155$$

$$155 — 34 = 121$$

Получаем: $$121$$.