Упр.575 ГДЗ Никольский Потапов 9 класс (Алгебра)
- а) $$1-\sin^2\alpha-\cos^2\alpha$$
- б) $$\sin^4\alpha-\cos^4\alpha$$
- в) $$\sin^4\alpha-\cos^4\alpha-\sin^2\alpha+\cos^2\alpha$$
- г) $$(\sin\alpha+\cos\alpha)^2+(\sin\alpha-\cos\alpha)^2$$
Воспользуемся основным тригонометрическим тождеством:
$$\sin^2 \alpha + \cos^2 \alpha = 1.$$
$$1-\sin^2 \alpha-\cos^2 \alpha$$
$$1-\sin^2 \alpha-\cos^2 \alpha=(\sin^2 \alpha+\cos^2 \alpha)-\sin^2 \alpha-\cos^2 \alpha=0.$$
$$\sin^4 \alpha-\cos^4 \alpha$$
$$\sin^4 \alpha-\cos^4 \alpha=(\sin^2 \alpha-\cos^2 \alpha)(\sin^2 \alpha+\cos^2 \alpha)=\sin^2 \alpha-\cos^2 \alpha.$$
$$\sin^4 \alpha-\cos^4 \alpha-\sin^2 \alpha+\cos^2 \alpha$$
$$\sin^4 \alpha-\cos^4 \alpha-\sin^2 \alpha+\cos^2 \alpha =(\sin^2 \alpha-\cos^2 \alpha)(\sin^2 \alpha+\cos^2 \alpha)-\sin^2 \alpha+\cos^2 \alpha$$
$$=\sin^2 \alpha-\cos^2 \alpha-\sin^2 \alpha+\cos^2 \alpha=0.$$
$$\left(\sin \alpha+\cos \alpha\right)^2+\left(\sin \alpha-\cos \alpha\right)^2$$
$$(\sin \alpha+\cos \alpha)^2+(\sin \alpha-\cos \alpha)^2 =\sin^2 \alpha+2\sin \alpha\cos \alpha+\cos^2 \alpha+\sin^2 \alpha-2\sin \alpha\cos \alpha+\cos^2 \alpha$$
$$=2\sin^2 \alpha+2\cos^2 \alpha=2(\sin^2 \alpha+\cos^2 \alpha)=2.$$
Ответ
а) $$0$$; б) $$\sin^2 \alpha-\cos^2 \alpha$$; в) $$0$$; г) $$2$$.












