Упр.1063 ГДЗ Макарычев Миндюк Феоктистов 9 класс (Алгебра)

1. $$\sin(-90^\circ)+\cos(-60^\circ) =-\sin90^\circ+\cos60^\circ =-1+\frac{1}{2} =-\frac{1}{2}$$
2. $$\tg(-45^\circ)-\ctg(-45^\circ) =-\tg45^\circ+\ctg45^\circ =-1+1=0$$
3. $$\cos\left(-\frac{\pi}{6}\right)-\sin\left(-\frac{\pi}{3}\right) =\cos\frac{\pi}{6}+\sin\frac{\pi}{3} =\cos30^\circ+\sin60^\circ =\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2} =\sqrt{3}$$
4. $$\ctg\left(-\frac{2\pi}{3}\right)+\tg\left(-\frac{\pi}{6}\right) =\ctg\frac{\pi}{3}-\tg\frac{\pi}{6} =\ctg60^\circ-\tg30^\circ =\frac{\sqrt{3}}{3}-\frac{\sqrt{3}}{3} =0$$

Ответ: $$-\frac{1}{2};\ 0;\ \sqrt{3};\ 0.$$