Упр.699 ГДЗ Никольский Потапов 8 класс (Алгебра)
б) 8-2р + 3р2 — 27р3;
в) (х2 + 4х)2 — (х — 9)2;
г) (9×2 + 2)2 — (6х + 7)2;
д) (5а — 7b)2 — 2(5а — 7b) + 1;
е) 1 + 2(х — 3у) + (х — 3у)2.
а) $$m^3-4m^2+20m-125=(m^3-125)-4m(m-5)$$
$$=(m-5)(m^2+5m+25)-4m(m-5)$$
$$=(m-5)(m^2+5m+25-4m)=(m-5)(m^2+m+25).$$
б) $$8-2p+3p^2-27p^3=(8-27p^3)-p(2-3p)$$
$$=(2-3p)(4+6p+9p^2)-p(2-3p)$$
$$=(2-3p)(4+6p+9p^2-p)=(2-3p)(4+5p+9p^2).$$
в) $$\left(x^2+4x\right)^2-(x-9)^2$$
$$=\left(x^2+4x-x+9\right)\left(x^2+4x+x-9\right)$$
$$=(x^2+3x+9)(x^2+5x-9).$$
г) $$\left(9x^2+2\right)^2-(6x+7)^2$$
$$=\left(9x^2+2-6x-7\right)\left(9x^2+2+6x+7\right)$$
$$=(9x^2-6x-5)(9x^2+6x+9)$$
$$=3(9x^2-6x-5)(3x^2+2x+3).$$
д) $$\left(5a-7b\right)^2-2\left(5a-7b\right)+1=\left(5a-7b-1\right)^2.$$
е) $$1+2(x-3y)+(x-3y)^2=\left(1+x-3y\right)^2.$$
Ответ
а) $$\left(m-5\right)\left(m^2+m+25\right);$$ б) $$\left(2-3p\right)\left(4+5p+9p^2\right);$$ в) $$\left(x^2+3x+9\right)\left(x^2+5x-9\right);$$ г) $$3\left(9x^2-6x-5\right)\left(3x^2+2x+3\right);$$ д) $$\left(5a-7b-1\right)^2;$$ е) $$\left(1+x-3y\right)^2.$$