Упр.361 ГДЗ Макарычев Миндюк Феоктистов 8 класс (Алгебра)

Выполним действия.

1. $$\frac{4}{7}\cdot\frac{14}{5}:\frac{2}{5} =\frac{4}{7}\cdot\frac{14}{5}\cdot\frac{5}{2} =4$$
2. $$\left(\frac{2}{3}-\frac{5}{8}\right):\frac{1}{8} =\left(\frac{16}{24}-\frac{15}{24}\right)\cdot 8 =\frac{1}{24}\cdot 8 =\frac{1}{3}$$
3. $$\left(\frac{1}{4}-\frac{2}{5}\right)\cdot\frac{6}{5} =\left(\frac{5}{20}-\frac{8}{20}\right)\cdot\frac{6}{5} =-\frac{3}{20}\cdot\frac{6}{5} =-\frac{9}{50}$$
4. $$\frac{7}{15}:\frac{5}{2}\cdot 3:9 =\frac{7}{15}\cdot\frac{2}{5}\cdot 3\cdot\frac{1}{9} =\frac{14}{225}$$
5. $$\frac{2}{3}\cdot\left(1-\frac{5}{6}\right):\frac{1}{3} =\frac{2}{3}\cdot\frac{1}{6}\cdot 3 =\frac{1}{3}$$
6. $$\frac{5}{3}:\left(2-\frac{5}{3}\right)\cdot\frac{1}{2} =\frac{5}{3}:\frac{1}{3}\cdot\frac{1}{2} =\frac{5}{3}\cdot 3\cdot\frac{1}{2} =\frac{5}{2}$$

Ответ: $$4;\ \frac{1}{3};\ -\frac{9}{50};\ \frac{14}{225};\ \frac{1}{3};\ \frac{5}{2}.$$