Упр.216 ГДЗ Муравин 7 класс (Алгебра)
1) x^6; 4) 0,4^3; 7) (ax)^6; 10) (a+2)^3;
2) y^5; 5) (2/3)^4; 8) (-7/9 b)^2; 11) (c-5)^4;
3) (-k)^7; 6) (-3t)^5; 9) (-by)^7; 12) (2t+1)^2.
- $$x^6=x\cdot x\cdot x\cdot x\cdot x\cdot x$$
- $$y^5=y\cdot y\cdot y\cdot y\cdot y$$
- $$(-k)^7=(-k)\cdot(-k)\cdot(-k)\cdot(-k)\cdot(-k)\cdot(-k)\cdot(-k)$$
- $$0{,}4^3=0{,}4\cdot0{,}4\cdot0{,}4$$
- $$\left(\frac{2}{3}\right)^4=\frac{2}{3}\cdot\frac{2}{3}\cdot\frac{2}{3}\cdot\frac{2}{3}$$
- $$(-3t)^5=(-3t)\cdot(-3t)\cdot(-3t)\cdot(-3t)\cdot(-3t)$$
- $$ (ax)^6=(ax)\cdot(ax)\cdot(ax)\cdot(ax)\cdot(ax)\cdot(ax) $$
- $$\left(-\frac{7}{9}b\right)^2=\left(-\frac{7}{9}b\right)\cdot\left(-\frac{7}{9}b\right)$$
- $$(-by)^7=(-by)\cdot(-by)\cdot(-by)\cdot(-by)\cdot(-by)\cdot(-by)\cdot(-by)$$
- $$ (a+2)^3=(a+2)\cdot(a+2)\cdot(a+2) $$
- $$ (c-5)^4=(c-5)\cdot(c-5)\cdot(c-5)\cdot(c-5) $$
- $$ (2t+1)^2=(2t+1)\cdot(2t+1) $$
Ответ
$$x^6=x\cdot x\cdot x\cdot x\cdot x\cdot x,\quad y^5=y\cdot y\cdot y\cdot y\cdot y,\quad (-k)^7=(-k)\cdot(-k)\cdot(-k)\cdot(-k)\cdot(-k)\cdot(-k)\cdot(-k),$$
$$0{,}4^3=0{,}4\cdot0{,}4\cdot0{,}4,\quad \left(\frac{2}{3}\right)^4=\frac{2}{3}\cdot\frac{2}{3}\cdot\frac{2}{3}\cdot\frac{2}{3},\quad (-3t)^5=(-3t)\cdot(-3t)\cdot(-3t)\cdot(-3t)\cdot(-3t),$$
$$ (ax)^6=(ax)\cdot(ax)\cdot(ax)\cdot(ax)\cdot(ax)\cdot(ax),\quad \left(-\frac{7}{9}b\right)^2=\left(-\frac{7}{9}b\right)\cdot\left(-\frac{7}{9}b\right),$$
$$(-by)^7=(-by)\cdot(-by)\cdot(-by)\cdot(-by)\cdot(-by)\cdot(-by)\cdot(-by),\quad (a+2)^3=(a+2)\cdot(a+2)\cdot(a+2),$$
$$ (c-5)^4=(c-5)\cdot(c-5)\cdot(c-5)\cdot(c-5),\quad (2t+1)^2=(2t+1)\cdot(2t+1). $$