Упр.33.12 ГДЗ Мордкович 7 класс (Алгебра)

б) (4×2-3c)2;
в) (5m2+3n2)2;
г) (6p2-8g3)2.

1. $$\left(a^3+3b\right)^2=(a^3)^2+2\cdot a^3\cdot 3b+(3b)^2=a^6+6a^3b+9b^2.$$
2. $$\left(4x^2-3c\right)^2=(4x^2)^2-2\cdot 4x^2\cdot 3c+(3c)^2=16x^4-24x^2c+9c^2.$$
3. $$\left(5m^2+3n^2\right)^2=(5m^2)^2+2\cdot 5m^2\cdot 3n^2+(3n^2)^2=25m^4+30m^2n^2+9n^4.$$
4. $$\left(6p^2-8g^3\right)^2=(6p^2)^2-2\cdot 6p^2\cdot 8g^3+(8g^3)^2=36p^4-96p^2g^3+64g^6.$$

Ответ

а) $$a^6+6a^3b+9b^2$$
б) $$16x^4-24x^2c+9c^2$$
в) $$25m^4+30m^2n^2+9n^4$$
г) $$36p^4-96p^2g^3+64g^6$$