Упр.27.14 ГДЗ Мордкович 7 класс (Алгебра)

1. а) $$(2m^2n^2)^4:(4mn)^2$$; б) $$5^5p^3q^4:(5pq)^0$$; в) $$(-x^2y^3z^4)^5:(-xyz)^8$$; г) $$(-5ac^3d)^3:(5cd)^2$$.

1. $$\left(2m^2n^2\right)^4 : \left(4mn\right)^2 = \frac{2^4m^8n^8}{4^2m^2n^2} = \frac{16m^8n^8}{16m^2n^2} = m^6n^6.$$
2. $$55p^3q^4 : \left(5pq\right)^0 = 55p^3q^4,$$
   так как $$\left(5pq\right)^0=1.$$
3. $$\left(-x^2y^3z^4\right)^5 : \left(-xyz\right)^8 = \frac{-x^{10}y^{15}z^{20}}{x^8y^8z^8} = -x^2y^7z^{12}.$$
4. $$\left(-5ac^3d\right)^3 : \left(5cd\right)^2 = \frac{-125a^3c^9d^3}{25c^2d^2} = -5a^3c^7d.$$

Ответ

а) $$m^6n^6$$; б) $$55p^3q^4$$; в) $$-x^2y^7z^{12}$$; г) $$-5a^3c^7d$$.