Упр.38.10 ГДЗ Мерзляк Поляков 7 класс (Алгебра)

1) (a^6/b^3 )^10;
2) (-4m/(9n^3 ))^2;
3) (-(10c^7)/(3d^5 ))^3;
4) ((2m^3 n^2)/(kp^8 ))^6.

1. $$\left(\frac{a^6}{b^3}\right)^{10}=\frac{(a^6)^{10}}{(b^3)^{10}}=\frac{a^{60}}{b^{30}}.$$
2. $$\left(\frac{-4m}{9n^3}\right)^2=\frac{(-4m)^2}{(9n^3)^2}=\frac{16m^2}{81n^6}.$$
3. $$\left(\frac{-10c^7}{3d^5}\right)^3=\frac{(-10c^7)^3}{(3d^5)^3}=\frac{-1000c^{21}}{27d^{15}}.$$
4. $$\left(\frac{2m^3n^2}{kp^8}\right)^6=\frac{(2m^3n^2)^6}{(kp^8)^6}=\frac{64m^{18}n^{12}}{k^6p^{48}}.$$

Ответ

1) $$\frac{a^{60}}{b^{30}}$$; 2) $$\frac{16m^2}{81n^6}$$; 3) $$-\frac{1000c^{21}}{27d^{15}}$$; 4) $$\frac{64m^{18}n^{12}}{k^6p^{48}}$$.