Упр.35.1 ГДЗ Мерзляк Поляков 7 класс (Алгебра)

1) (14a^3)/21a;
2) (24x^2 y^2)/32xy;
3) 4abc/(16ab^4 );
4) (56m^5 n^7)/(42m^5 n^10 );
5) (-10n^10)/(5n^4 );
6) (3p^4 q^6)/(-9p^8 q^7 ).

1. $$\frac{14a^3}{21a}=\frac{14}{21}\cdot\frac{a^3}{a}=\frac{2}{3}\cdot a^2=\frac{2a^2}{3}.$$
2. $$\frac{24x^2y^2}{32xy}=\frac{24}{32}\cdot\frac{x^2}{x}\cdot\frac{y^2}{y}=\frac{3}{4}\cdot x\cdot y=\frac{3xy}{4}.$$
3. $$\frac{4abc}{16ab^4}=\frac{4}{16}\cdot\frac{a}{a}\cdot\frac{b}{b^4}\cdot c=\frac{1}{4}\cdot\frac{c}{b^3}=\frac{c}{4b^3}.$$
4. $$\frac{56m^5n^7}{42m^5n^{10}}=\frac{56}{42}\cdot\frac{m^5}{m^5}\cdot\frac{n^7}{n^{10}}=\frac{4}{3}\cdot\frac{1}{n^3}=\frac{4}{3n^3}.$$
5. $$\frac{-10n^{10}}{5n^4}=\frac{-10}{5}\cdot n^{10-4}=-2n^6.$$
6. $$\frac{3p^4q^6}{-9p^8q^7}=\frac{3}{-9}\cdot\frac{p^4}{p^8}\cdot\frac{q^6}{q^7}=-\frac{1}{3}\cdot\frac{1}{p^4}\cdot\frac{1}{q}=-\frac{1}{3p^4q}.$$

Ответ

1) $$\frac{2a^2}{3}$$; 2) $$\frac{3xy}{4}$$; 3) $$\frac{c}{4b^3}$$; 4) $$\frac{4}{3n^3}$$; 5) $$-2n^6$$; 6) $$-\frac{1}{3p^4q}$$.