Упр.17.25 ГДЗ Никольский Потапов 11 класс (Алгебра)

а) 1;
б) —1;
в) 8i;
г) -8i;
д) 1 + i;
е) 1 — i;
ж) 1 + корень 3;
з) 1 — i корень 3.

1. $$z=1=\cos 0+i\sin 0$$

   Тогда корни третьей степени:

   $$ \sqrt[3]{1}=\cos \frac{2\pi k}{3}+i\sin \frac{2\pi k}{3}, \quad k=0,1,2 $$

   $$ \alpha_0=1,\quad \alpha_1=\cos \frac{2\pi}{3}+i\sin \frac{2\pi}{3}=-\frac12+\frac{\sqrt3}{2}i,\quad \alpha_2=\cos \frac{4\pi}{3}+i\sin \frac{4\pi}{3}=-\frac12-\frac{\sqrt3}{2}i $$

2. $$z=-1=\cos \pi+i\sin \pi$$

   $$ \sqrt[3]{-1}=\cos \frac{\pi+2\pi k}{3}+i\sin \frac{\pi+2\pi k}{3}, \quad k=0,1,2 $$

   $$ \alpha_0=\cos \frac{\pi}{3}+i\sin \frac{\pi}{3}=\frac12+\frac{\sqrt3}{2}i $$

   $$ \alpha_1=\cos \pi+i\sin \pi=-1 $$

   $$ \alpha_2=\cos \frac{5\pi}{3}+i\sin \frac{5\pi}{3}=\frac12-\frac{\sqrt3}{2}i $$

3. $$z=8i=8\left(\cos \frac{\pi}{2}+i\sin \frac{\pi}{2}\right)$$

   $$ \sqrt[3]{8i}=2\left(\cos \frac{\frac{\pi}{2}+2\pi k}{3}+i\sin \frac{\frac{\pi}{2}+2\pi k}{3}\right), \quad k=0,1,2 $$

   $$ \alpha_0=2\left(\cos \frac{\pi}{6}+i\sin \frac{\pi}{6}\right)=\sqrt3+i $$

   $$ \alpha_1=2\left(\cos \frac{5\pi}{6}+i\sin \frac{5\pi}{6}\right)=-\sqrt3+i $$

   $$ \alpha_2=2\left(\cos \frac{3\pi}{2}+i\sin \frac{3\pi}{2}\right)=-2i $$

4. $$z=-8i=8\left(\cos \frac{3\pi}{2}+i\sin \frac{3\pi}{2}\right)$$

   $$ \sqrt[3]{-8i}=2\left(\cos \frac{\frac{3\pi}{2}+2\pi k}{3}+i\sin \frac{\frac{3\pi}{2}+2\pi k}{3}\right), \quad k=0,1,2 $$

   $$ \alpha_0=2\left(\cos \frac{\pi}{2}+i\sin \frac{\pi}{2}\right)=2i $$

   $$ \alpha_1=2\left(\cos \frac{7\pi}{6}+i\sin \frac{7\pi}{6}\right)=-\sqrt3-i $$

   $$ \alpha_2=2\left(\cos \frac{11\pi}{6}+i\sin \frac{11\pi}{6}\right)=\sqrt3-i $$

5. $$z=1+i=\sqrt2\left(\cos \frac{\pi}{4}+i\sin \frac{\pi}{4}\right)$$

   $$ \sqrt[3]{1+i}=\sqrt[6]{2}\left(\cos \frac{\frac{\pi}{4}+2\pi k}{3}+i\sin \frac{\frac{\pi}{4}+2\pi k}{3}\right), \quad k=0,1,2 $$

   $$ \alpha_0=\sqrt[6]{2}\left(\cos \frac{\pi}{12}+i\sin \frac{\pi}{12}\right) $$

   $$ \alpha_1=\sqrt[6]{2}\left(\cos \frac{3\pi}{4}+i\sin \frac{3\pi}{4}\right) =\sqrt[6]{2}\left(-\frac{\sqrt2}{2}+i\frac{\sqrt2}{2}\right) =-\frac{1}{\sqrt[3]{2}}+\frac{i}{\sqrt[3]{2}} $$

   $$ \alpha_2=\sqrt[6]{2}\left(\cos \frac{17\pi}{12}+i\sin \frac{17\pi}{12}\right) $$

6. $$z=1-i=\sqrt2\left(\cos \frac{7\pi}{4}+i\sin \frac{7\pi}{4}\right)$$

   $$ \sqrt[3]{1-i}=\sqrt[6]{2}\left(\cos \frac{\frac{7\pi}{4}+2\pi k}{3}+i\sin \frac{\frac{7\pi}{4}+2\pi k}{3}\right), \quad k=0,1,2 $$

   $$ \alpha_0=\sqrt[6]{2}\left(\cos \frac{7\pi}{12}+i\sin \frac{7\pi}{12}\right) $$

   $$ \alpha_1=\sqrt[6]{2}\left(\cos \frac{5\pi}{4}+i\sin \frac{5\pi}{4}\right) =\sqrt[6]{2}\left(-\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right) $$

   $$ \alpha_2=\sqrt[6]{2}\left(\cos \frac{23\pi}{12}+i\sin \frac{23\pi}{12}\right) $$

7. $$z=1+i\sqrt3=2\left(\cos \frac{\pi}{3}+i\sin \frac{\pi}{3}\right)$$

   $$ \sqrt[3]{1+i\sqrt3}=\sqrt[3]{2}\left(\cos \frac{\frac{\pi}{3}+2\pi k}{3}+i\sin \frac{\frac{\pi}{3}+2\pi k}{3}\right), \quad k=0,1,2 $$

   $$ \alpha_0=\sqrt[3]{2}\left(\cos \frac{\pi}{9}+i\sin \frac{\pi}{9}\right) $$

   $$ \alpha_1=\sqrt[3]{2}\left(\cos \frac{7\pi}{9}+i\sin \frac{7\pi}{9}\right) $$

   $$ \alpha_2=\sqrt[3]{2}\left(\cos \frac{13\pi}{9}+i\sin \frac{13\pi}{9}\right) $$

8. $$z=1-i\sqrt3=2\left(\cos \frac{5\pi}{3}+i\sin \frac{5\pi}{3}\right)$$

   $$ \sqrt[3]{1-i\sqrt3}=\sqrt[3]{2}\left(\cos \frac{\frac{5\pi}{3}+2\pi k}{3}+i\sin \frac{\frac{5\pi}{3}+2\pi k}{3}\right), \quad k=0,1,2 $$

   $$ \alpha_0=\sqrt[3]{2}\left(\cos \frac{5\pi}{9}+i\sin \frac{5\pi}{9}\right) $$

   $$ \alpha_1=\sqrt[3]{2}\left(\cos \frac{11\pi}{9}+i\sin \frac{11\pi}{9}\right) $$

   $$ \alpha_2=\sqrt[3]{2}\left(\cos \frac{17\pi}{9}+i\sin \frac{17\pi}{9}\right) $$

Ответ

а) $$1,\; -\frac12+\frac{\sqrt3}{2}i,\; -\frac12-\frac{\sqrt3}{2}i$$

б) $$\frac12+\frac{\sqrt3}{2}i,\; -1,\; \frac12-\frac{\sqrt3}{2}i$$

в) $$\sqrt3+i,\; -\sqrt3+i,\; -2i$$

г) $$2i,\; -\sqrt3-i,\; \sqrt3-i$$

д) $$\sqrt[6]{2}\left(\cos \frac{\pi}{12}+i\sin \frac{\pi}{12}\right),\; -\frac{1}{\sqrt[3]{2}}+\frac{i}{\sqrt[3]{2}},\; \sqrt[6]{2}\left(\cos \frac{17\pi}{12}+i\sin \frac{17\pi}{12}\right)$$

е) $$\sqrt[6]{2}\left(\cos \frac{7\pi}{12}+i\sin \frac{7\pi}{12}\right),\; \sqrt[6]{2}\left(\cos \frac{5\pi}{4}+i\sin \frac{5\pi}{4}\right),\; \sqrt[6]{2}\left(\cos \frac{23\pi}{12}+i\sin \frac{23\pi}{12}\right)$$

ж) $$\sqrt[3]{2}\left(\cos \frac{\pi}{9}+i\sin \frac{\pi}{9}\right),\; \sqrt[3]{2}\left(\cos \frac{7\pi}{9}+i\sin \frac{7\pi}{9}\right),\; \sqrt[3]{2}\left(\cos \frac{13\pi}{9}+i\sin \frac{13\pi}{9}\right)$$

з) $$\sqrt[3]{2}\left(\cos \frac{5\pi}{9}+i\sin \frac{5\pi}{9}\right),\; \sqrt[3]{2}\left(\cos \frac{11\pi}{9}+i\sin \frac{11\pi}{9}\right),\; \sqrt[3]{2}\left(\cos \frac{17\pi}{9}+i\sin \frac{17\pi}{9}\right)$$