Упр.43 Повторение ГДЗ Мерзляк 11 класс Базовый уровень (Алгебра)

1) (13/18-5/9)·3/20; 6) 2 4/9:(5/12-1/9);
2) 13/18-5/9·3/20; 7) (-5,16+5,02)·(2,5-4);
3) 1 3/25·2 1/7-1 8/9·27/170; 8) 5/32:5/12-3 1/4:1 2/11;
4) (9-2 1/7·3 1/9)·27/35; 9) (7-1 5/9:7/24):(-25/36);
5) (5 1/16-1 1/8)(5/6-1/14); 10) (28,9:(-17/20)-2,08:(-1/25)):(-1 2/7).

1. $$\left(\frac{13}{18}-\frac{5}{9}\right)\cdot\frac{3}{20}=\left(\frac{13}{18}-\frac{10}{18}\right)\cdot\frac{3}{20}=\frac{3}{18}\cdot\frac{3}{20}=\frac{1}{6}\cdot\frac{3}{20}=\frac{1}{40}.$$
2. $$\frac{13}{18}-\frac{5}{9}\cdot\frac{3}{20}=\frac{13}{18}-\frac{1}{12}=\frac{26}{36}-\frac{3}{36}=\frac{23}{36}.$$
3. $$1\frac{3}{25}\cdot2\frac{1}{7}-1\frac{8}{9}\cdot\frac{27}{170}=\frac{28}{25}\cdot\frac{15}{7}-\frac{17}{9}\cdot\frac{27}{170}=\frac{4\cdot3}{5}-\frac{3\cdot12}{5\cdot10}=2{,}4-0{,}3=2{,}1.$$
4. $$\left(9-2\frac{1}{7}\cdot3\frac{1}{9}\right)\cdot\frac{27}{35}=\left(9-\frac{15}{7}\cdot\frac{28}{9}\right)\cdot\frac{27}{35}=\left(9-\frac{20}{3}\right)\cdot\frac{27}{35}=\frac{7}{3}\cdot\frac{27}{35}=1{,}8.$$
5. $$\left(5\frac{1}{16}-1\frac{1}{8}\right)\left(\frac{5}{6}-\frac{1}{14}\right)=\left(\frac{81}{16}-\frac{9}{8}\right)\left(\frac{35}{42}-\frac{3}{42}\right)=\frac{63}{16}\cdot\frac{32}{42}=3.$$
6. $$2\frac{4}{9}:\left(\frac{5}{12}-\frac{1}{9}\right)=\frac{22}{9}:\left(\frac{15-4}{36}\right)=\frac{22}{9}:\frac{11}{36}=2\cdot4=8.$$
7. $$(-5{,}16+5{,}02)\cdot(2{,}5-4)=-0{,}14\cdot(-1{,}5)=0{,}21.$$
8. $$\frac{5}{32}:\frac{5}{12}-3\frac{1}{4}:1\frac{2}{11}=\frac{5}{32}\cdot\frac{12}{5}-\frac{13}{4}:\frac{13}{11}=\frac{3}{8}-\frac{11}{4}=\frac{3-22}{8}=-\frac{19}{8}=-2\frac{3}{8}.$$
9. $$\left(7-1\frac{5}{9}:\frac{7}{24}\right):\left(-\frac{25}{36}\right)=\left(7-\frac{14}{9}\cdot\frac{24}{7}\right):\left(-\frac{25}{36}\right)=\left(7-\frac{48}{9}\right):\left(-\frac{25}{36}\right)=\frac{5}{3}\cdot\left(-\frac{36}{25}\right)=-2{,}4.$$
10. $$\left(28{,}9:\left(-\frac{17}{20}\right)-2{,}08:\left(-\frac{1}{25}\right)\right):\left(-1\frac{2}{7}\right)=\left(\frac{28{,}9}{-0{,}85}-\frac{2{,}08}{-0{,}04}\right):\left(-\frac{9}{7}\right)=(-34+52)\cdot\left(-\frac{7}{9}\right)=18\cdot\left(-\frac{7}{9}\right)=-14.$$

Ответ

1) $$\frac{1}{40}$$; 2) $$\frac{23}{36}$$; 3) $$2{,}1$$; 4) $$1{,}8$$; 5) $$3$$; 6) $$8$$; 7) $$0{,}21$$; 8) $$-\frac{19}{8}$$; 9) $$-2{,}4$$; 10) $$-14$$.