Упр.28.352 ГДЗ Мерзляк 11 класс Углубленный уровень (Алгебра)
1) 3^x-2·3^(x-2)=7;
2) 2^(x+1)+2^(x-3)=68;
3) 7^x-(1/7)^(1-x)=6;
4) 4^(x/2)+2^(x-5)-2^(x-7)=262;
5) 2^(x-1)+2^(x-2)+2^(x-3)=3^(x-1)-3^(x-2)+3^(x-3);
6) 2^(2x-1)+2^(2x-3)-2^(2x-5)=2^(7-x)+2^(5-x)-2^(3-x).
$$3^x-2\cdot 3^{x-2}=7$$
$$3^x-2\cdot \frac{3^x}{9}=7$$
$$3^x\left(1-\frac{2}{9}\right)=7$$
$$3^x\cdot \frac{7}{9}=7$$
$$3^x=9$$
$$x=2$$$$2^{x+1}+2^{x-3}=68$$
$$2^x\left(2+\frac{1}{8}\right)=68$$
$$2^x\cdot \frac{17}{8}=68$$
$$2^x=32$$
$$x=5$$$$7^x-\left(\frac{1}{7}\right)^{1-x}=6$$
$$\left(\frac{1}{7}\right)^{1-x}=7^{x-1}$$
$$7^x-7^{x-1}=6$$
$$7^{x-1}(7-1)=6$$
$$7^{x-1}\cdot 6=6$$
$$7^{x-1}=1$$
$$x-1=0$$
$$x=1$$$$4^{x/2}+2^{x-5}-2^{x-7}=262$$
$$2^x+2^{x-5}-2^{x-7}=262$$
$$2^x\left(1+\frac{1}{32}-\frac{1}{128}\right)=262$$
$$2^x\cdot \frac{131}{128}=262$$
$$2^x=256$$
$$x=8$$$$2^{x-1}+2^{x-2}+2^{x-3}=3^{x-1}-3^{x-2}+3^{x-3}$$
$$2^x\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)=3^x\left(\frac{1}{3}-\frac{1}{9}+\frac{1}{27}\right)$$
$$2^x\cdot \frac{7}{8}=3^x\cdot \frac{7}{27}$$
$$\left(\frac{2}{3}\right)^x=\frac{8}{27}$$
$$\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^3$$
$$x=3$$$$2^{2x-1}+2^{2x-3}-2^{2x-5}=2^{7-x}+2^{5-x}-2^{3-x}$$
$$2^{2x}\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{32}\right)=2^{-x}(128+32-8)$$
$$2^{2x}\cdot \frac{19}{32}=2^{-x}\cdot 152$$
$$2^{2x}\cdot 19=2^{-x}\cdot 152\cdot 32$$
$$2^{2x}=2^{8-x}$$
$$2x=8-x$$
$$3x=8$$
$$x=\frac{8}{3}$$
Ответ
1) $$2$$; 2) $$5$$; 3) $$1$$; 4) $$8$$; 5) $$3$$; 6) $$\frac{8}{3}$$.
