Упр.838 ГДЗ Колягин Ткачёва 11 класс (Алгебра)
2) 2^х+4 — 2х = 120;
3) 5х + 1 + 5х + 5х -1 = 155;
4) 3^2х-2 * 3^2х-1 -2 * 3^2x-2=1;
5) 7х-7х-1 = 6;
6) 3х + 2 + Зх= 10.
$$9^{5x}-9^{5x-1}=8$$
$$9^{5x}\left(1-\frac{1}{9}\right)=8$$
$$9^{5x}\cdot \frac{8}{9}=8$$
$$9^{5x}=9$$
$$9^{5x}=9^1 \Rightarrow 5x=1 \Rightarrow x=\frac{1}{5}$$
$$2^{x+4}-2^x=120$$
$$2^x\left(2^4-1\right)=120$$
$$2^x\cdot 15=120$$
$$2^x=8=2^3 \Rightarrow x=3$$
$$5^{x+1}+5^x+5^{x-1}=155$$
$$5^x\left(5+1+\frac{1}{5}\right)=155$$
$$5^x\cdot \frac{31}{5}=155$$
$$5^x=25=5^2 \Rightarrow x=2$$
$$3^{2x}-2\cdot 3^{2x-1}-2\cdot 3^{2x-2}=1$$
$$3^{2x}\left(1-\frac{2}{3}-\frac{2}{9}\right)=1$$
$$3^{2x}\cdot \frac{1}{9}=1$$
$$3^{2x}=9=3^2 \Rightarrow 2x=2 \Rightarrow x=1$$
$$7^x-7^{x-1}=6$$
$$7^x\left(1-\frac{1}{7}\right)=6$$
$$7^x\cdot \frac{6}{7}=6$$
$$7^x=7=7^1 \Rightarrow x=1$$
$$3^{x+2}+3^x=10$$
$$3^x\left(3^2+1\right)=10$$
$$3^x\cdot 10=10$$
$$3^x=1=3^0 \Rightarrow x=0$$
Ответ
1) $$\frac{1}{5}$$; 2) $$3$$; 3) $$2$$; 4) $$1$$; 5) $$1$$; 6) $$0$$.