Упр.835 ГДЗ Алимов 10-11 класс (Алгебра)
2) 3 ln x — 2x;
3) log2 x + 1/2x;
4) 3 x^-3 — log3(x);
5) ln (x2 — 2x);
6) (3×2 — 2) log3(x).
$$f(x)=2\ln x+3^x$$
$$f'(x)=(2\ln x)’+(3^x)’=\frac{2}{x}+3^x\ln 3$$
$$f(x)=3\ln x-2^x$$
$$f'(x)=(3\ln x)’-(2^x)’=\frac{3}{x}-2^x\ln 2$$
$$f(x)=\log_2 x+\frac{1}{2x}$$
$$f'(x)=(\log_2 x)’+\left(\frac{1}{2x}\right)’=\frac{1}{x\ln 2}-\frac{1}{2x^2}$$
$$f(x)=3x^{-3}-\log_3 x$$
$$f'(x)=(3x^{-3})’-(\log_3 x)’=3\cdot(-3)x^{-4}-\frac{1}{x\ln 3}=-9x^{-4}-\frac{1}{x\ln 3}$$
$$f(x)=\ln(x^2-2x)$$
Область определения: $$x^2-2x>0$$.
$$f'(x)=\frac{(x^2-2x)’}{x^2-2x}=\frac{2x-2}{x^2-2x}$$
$$f(x)=(3x^2-2)\log_3 x$$
$$f'(x)=(3x^2-2)’\log_3 x+(3x^2-2)(\log_3 x)’$$
$$f'(x)=6x\log_3 x+(3x^2-2)\cdot\frac{1}{x\ln 3}$$
$$f'(x)=\frac{6x^2\ln x+3x^2-2}{x\ln 3}=\frac{3x^2(2\ln x+1)-2}{x\ln 3}$$
Ответ
- $$\frac{2}{x}+3^x\ln 3$$
- $$\frac{3}{x}-2^x\ln 2$$
- $$\frac{1}{x\ln 2}-\frac{1}{2x^2}$$
- $$-9x^{-4}-\frac{1}{x\ln 3}$$
- $$\frac{2x-2}{x^2-2x}$$
- $$\frac{3x^2(2\ln x+1)-2}{x\ln 3}$$