Упражнение 2 Повторение ГДЗ Никольский 10 класс (Алгебра)

1. а)

   $$\left(0{,}2-\frac{12}{75}\right)\cdot 0{,}5+3{,}5\cdot 3{,}5-\left(\frac{6}{25}-\frac{12}{75}\right)\cdot 0{,}5+\frac{35}{100}:\frac{25}{10}$$

   $$0{,}2=\frac15,\quad 0{,}5=\frac12,\quad 3{,}5=\frac72,\quad \frac{12}{75}=\frac4{25}$$

   $$\left(\frac15-\frac4{25}\right)\cdot\frac12+\frac72\cdot\frac72-\left(\frac6{25}-\frac4{25}\right)\cdot\frac12+\frac{35}{100}\cdot\frac{10}{25}$$

   $$\frac1{25}+\frac{49}{4}-\frac1{25}+\frac7{20}=\frac{49}{4}+\frac7{20}=\frac{245}{20}+\frac7{20}=\frac{252}{20}=\frac{63}{5}=12{,}6$$

2. б)

   $$\left(\frac35+\frac14-\frac18\right)\cdot 3{,}2+\frac9{20}:10$$

   $$3{,}2=\frac{16}{5},\quad \frac9{20}:10=\frac9{20}\cdot\frac1{10}=\frac9{200}$$

   $$\left(\frac35+\frac14-\frac18\right)\cdot\frac{16}{5}+\frac9{200}$$

   $$\frac{24}{40}+\frac{10}{40}-\frac{5}{40}=\frac{29}{40}$$

   $$\frac{29}{40}\cdot\frac{16}{5}+\frac9{200}=\frac{58}{25}+\frac9{200}=\frac{464}{200}+\frac9{200}=\frac{473}{200}=2{,}365$$

3. в)

   $$\left(-6\frac{2}{15}-1\frac{1}{12}+\frac{13}{60}\right):0{,}5+11$$

   $$-6\frac{2}{15}=-\frac{92}{15},\quad -1\frac{1}{12}=-\frac{13}{12},\quad 0{,}5=\frac12$$

   $$\left(-\frac{92}{15}-\frac{13}{12}+\frac{13}{60}\right):\frac12+11$$

   $$-\frac{368}{60}-\frac{65}{60}+\frac{13}{60}=-\frac{420}{60}=-7$$

   $$-7:\frac12+11=-14+11=-3$$

Ответ

а) $$12{,}6$$; б) $$2{,}365$$; в) $$-3$$.