Упр.28.3 ГДЗ Мордковича 10 класс профильный уровень (Алгебра)
- а) $$\sin\frac{\pi}{5}-\sin\frac{\pi}{10}$$
- б) $$\sin\frac{\pi}{3}+\sin\frac{\pi}{4}$$
- в) $$\sin\frac{\pi}{6}+\sin\frac{\pi}{7}$$
- г) $$\sin\frac{\pi}{3}-\sin\frac{\pi}{11}$$
Используем формулы приведения суммы и разности синусов:
$$\sin \alpha-\sin \beta=2\sin \frac{\alpha-\beta}{2}\cos \frac{\alpha+\beta}{2},$$
$$\sin \alpha+\sin \beta=2\sin \frac{\alpha+\beta}{2}\cos \frac{\alpha-\beta}{2}.$$
$$\sin \frac{\pi}{5}-\sin \frac{\pi}{10}=2\sin \frac{\frac{\pi}{5}-\frac{\pi}{10}}{2}\cos \frac{\frac{\pi}{5}+\frac{\pi}{10}}{2}=2\sin \frac{\pi}{20}\cos \frac{3\pi}{20}.$$
$$\sin \frac{\pi}{3}+\sin \frac{\pi}{4}=2\sin \frac{\frac{\pi}{3}+\frac{\pi}{4}}{2}\cos \frac{\frac{\pi}{3}-\frac{\pi}{4}}{2}=2\sin \frac{7\pi}{24}\cos \frac{\pi}{24}.$$
$$\sin \frac{\pi}{6}+\sin \frac{\pi}{7}=2\sin \frac{\frac{\pi}{6}+\frac{\pi}{7}}{2}\cos \frac{\frac{\pi}{6}-\frac{\pi}{7}}{2}=2\sin \frac{13\pi}{84}\cos \frac{\pi}{84}.$$
$$\sin \frac{\pi}{3}-\sin \frac{\pi}{11}=2\sin \frac{\frac{\pi}{3}-\frac{\pi}{11}}{2}\cos \frac{\frac{\pi}{3}+\frac{\pi}{11}}{2}=2\sin \frac{4\pi}{33}\cos \frac{7\pi}{33}.$$
Ответ: а) $$2\sin \frac{\pi}{20}\cos \frac{3\pi}{20}$$; б) $$2\sin \frac{7\pi}{24}\cos \frac{\pi}{24}$$; в) $$2\sin \frac{13\pi}{84}\cos \frac{\pi}{84}$$; г) $$2\sin \frac{4\pi}{33}\cos \frac{7\pi}{33}$$.









