Упр.1042 ГДЗ Колягин Ткачёва 10 класс (Алгебра)
1) tgatgb + (tga + tgb)ctg(a + b);
2) (tga — tgb)ctg(a -b) — tgatgb;
$$\tg a \tg b + (\tg a + \tg b)\ctg(a+b)$$
$$=\tg a \tg b + (\tg a + \tg b)\cdot \frac{1-\tg a \tg b}{\tg a+\tg b}$$
$$=\tg a \tg b + 1 — \tg a \tg b = 1.$$$$ (\tg a-\tg b)\ctg(a-b)-\tg a \tg b $$
$$=(\tg a-\tg b)\cdot \frac{1+\tg a \tg b}{\tg a-\tg b}-\tg a \tg b$$
$$=1+\tg a \tg b-\tg a \tg b=1.$$$$\frac{3\ctg^2 15^\circ-1}{3-\ctg^2 15^\circ}$$
$$=\frac{\ctg^2 30^\circ\cdot \ctg^2 15^\circ-1}{\ctg^2 30^\circ-\ctg^2 15^\circ}$$
$$=\frac{(\ctg 30^\circ\cdot \ctg 15^\circ-1)(\ctg 30^\circ\cdot \ctg 15^\circ+1)}{(\ctg 30^\circ+\ctg 15^\circ)(\ctg 30^\circ-\ctg 15^\circ)}$$
$$=\ctg(30^\circ+15^\circ)\cdot \ctg(15^\circ-30^\circ)$$
$$=\ctg 45^\circ\cdot \ctg(-15^\circ)=-\ctg 15^\circ.$$$$\frac{\tg 50^\circ-\tg 5^\circ-1}{\tg 50^\circ\cdot \tg 5^\circ}$$
$$=\frac{\tg(50^\circ-5^\circ)(1-\tg 50^\circ\cdot \tg 5^\circ)-1}{\tg 50^\circ\cdot \tg 5^\circ}$$
$$=\frac{\tg 45^\circ(1-\tg 50^\circ\cdot \tg 5^\circ)-1}{\tg 50^\circ\cdot \tg 5^\circ}$$
$$=\frac{1-\tg 50^\circ\cdot \tg 5^\circ-1}{\tg 50^\circ\cdot \tg 5^\circ}=-1.$$
Ответ
1) $$1$$;
2) $$1$$;
3) $$-\ctg 15^\circ$$;
4) $$-1$$.