Упр.15.13 ГДЗ Рабочая тетрадь Зубарева Мордкович 6 класс Экзамен (Математика)
- Выполните деление: а) $$18:10\frac{7}{20}$$; $$4\frac{1}{2}:\frac{2}{3}$$; $$5\frac{17}{24}:\frac{2}{3}$$; б) $$17\frac{5}{14}:2\frac{2}{27}$$; $$39:9\frac{3}{5}$$; $$\frac{7}{12}:3\frac{1}{16}$$; в) $$63\frac{1}{3}:5\frac{2}{11}$$; $$6\frac{1}{8}:3\frac{1}{2}$$; $$5\frac{9}{11}:13\frac{5}{7}$$; г) $$32:9\frac{3}{5}$$; $$25\frac{5}{7}:1\frac{1}{35}$$; $$21\frac{7}{9}:4\frac{2}{3}$$.
а) $$18:10\frac{7}{20}=18:\frac{207}{20}=18\cdot\frac{20}{207}=\frac{40}{23}=1\frac{17}{23};$$
$$4\frac{1}{2}:\frac{2}{3}=\frac{9}{2}\cdot\frac{3}{2}=\frac{27}{4}=6\frac{3}{4};$$
$$5\frac{17}{24}:\frac{2}{3}=\frac{137}{24}\cdot\frac{3}{2}=\frac{137}{16}=8\frac{9}{16}.$$
б) $$17\frac{5}{14}:2\frac{2}{27}=\frac{243}{14}:\frac{56}{27}=\frac{243}{14}\cdot\frac{27}{56}=\frac{6561}{784}=8\frac{289}{784};$$
$$39:9\frac{3}{5}=39:\frac{48}{5}=39\cdot\frac{5}{48}=\frac{65}{16}=4\frac{1}{16};$$
$$\frac{7}{12}:3\frac{1}{16}=\frac{7}{12}:\frac{49}{16}=\frac{7}{12}\cdot\frac{16}{49}=\frac{4}{21}.$$
в) $$63\frac{1}{3}:5\frac{2}{11}=\frac{190}{3}:\frac{57}{11}=\frac{190}{3}\cdot\frac{11}{57}=\frac{10}{3}\cdot\frac{11}{3}=\frac{110}{9}=12\frac{2}{9};$$
$$6\frac{1}{8}:3\frac{1}{2}=\frac{49}{8}:\frac{7}{2}=\frac{49}{8}\cdot\frac{2}{7}=\frac{7}{4}=1\frac{3}{4};$$
$$5\frac{9}{11}:13\frac{5}{7}=\frac{64}{11}:\frac{96}{7}=\frac{64}{11}\cdot\frac{7}{96}=\frac{14}{33}.$$
г) $$32:9\frac{3}{5}=32:\frac{48}{5}=32\cdot\frac{5}{48}=\frac{10}{3}=3\frac{1}{3};$$
$$25\frac{5}{7}:1\frac{1}{35}=\frac{180}{7}:\frac{36}{35}=\frac{180}{7}\cdot\frac{35}{36}=25;$$
$$21\frac{7}{9}:4\frac{2}{3}=\frac{196}{9}:\frac{14}{3}=\frac{196}{9}\cdot\frac{3}{14}=\frac{14}{3}=4\frac{2}{3}.$$
Ответ: а) $$1\frac{17}{23};\ 6\frac{3}{4};\ 8\frac{9}{16}$$; б) $$8\frac{289}{784};\ 4\frac{1}{16};\ \frac{4}{21}$$; в) $$12\frac{2}{9};\ 1\frac{3}{4};\ \frac{14}{33}$$; г) $$3\frac{1}{3};\ 25;\ 4\frac{2}{3}$$.
