Упр.946 ГДЗ Зубарева Мордкович 6 класс ФГОС (Математика)

а) (0,411-1 3/8-1 3/4) :0,59;
б) (1,35-6 8/15) :(2 4/5+0,2);
в) 12,8•0,25:(0,125-3/4);
г) ((1,5+2 2/3+3 3/4)•3,6)/(15 1/8 :2-14);
д) (2,7+1 1/3-1 4/5)•1 53/67;
е) 1 1/16 :(7 2/5-12 3/8+37,525);
ж) (3/7+0,7-1/10)•5 5/6;
з) ((1 7/25+12 3/5-8,9)•0,5)/(0,2388:796).

а) $$\left(0{,}411-1\frac{3}{8}-1\frac{3}{4}\right):0{,}59$$

$$1\frac{3}{8}=1\frac{6}{8},\quad 1\frac{3}{4}=1\frac{6}{8}$$

$$0{,}411-1\frac{3}{8}-1\frac{3}{4}=0{,}411-3{,}125=-2{,}714$$

$$-2{,}714:0{,}59=-4{,}6$$

б) $$\left(1{,}35-6\frac{8}{15}\right):\left(2\frac{4}{5}+0{,}2\right)$$

$$1{,}35=1\frac{35}{100}=1\frac{7}{20},\quad 0{,}2=\frac{1}{5}$$

$$1\frac{7}{20}-6\frac{8}{15}=1\frac{21}{60}-6\frac{32}{60}=-5\frac{11}{60}=-\frac{311}{60}$$

$$2\frac{4}{5}+0{,}2=2\frac{4}{5}+\frac{1}{5}=3$$

$$-\frac{311}{60}:3=-\frac{311}{180}=-1\frac{131}{180}$$

в) $$12{,}8\cdot 0{,}25:(0{,}125-\frac{3}{4})$$

$$12{,}8\cdot 0{,}25=3{,}2$$

$$0{,}125-\frac{3}{4}=0{,}125-0{,}75=-0{,}625$$

$$3{,}2:(-0{,}625)=-5{,}12$$

г) $$\frac{\left(1{,}5+2\frac{2}{3}+3\frac{3}{4}\right)\cdot 3{,}6}{15\frac{1}{8}:2-14}$$

$$1{,}5=1\frac{1}{2},\quad 2\frac{2}{3}=2\frac{8}{12},\quad 3\frac{3}{4}=3\frac{9}{12}$$

$$1\frac{1}{2}+2\frac{2}{3}+3\frac{3}{4}=6\frac{23}{12}=\frac{95}{12}$$

$$15\frac{1}{8}:2-14=\frac{121}{8}:2-14=\frac{121}{16}-14=-\frac{103}{16}$$

$$\frac{95}{12}\cdot 3{,}6=\frac{95}{12}\cdot \frac{36}{10}=\frac{19}{1}\cdot \frac{3}{2}=\frac{57}{2}$$

$$\frac{57}{2}:\left(-\frac{103}{16}\right)=\frac{57}{2}\cdot \frac{16}{-103}=-\frac{456}{103}=-4\frac{44}{103}$$

д) $$\left(2{,}7+1\frac{1}{3}-1\frac{4}{5}\right)\cdot 1\frac{53}{67}$$

$$2{,}7=2\frac{7}{10},\quad 1\frac{1}{3}=1\frac{5}{15},\quad 1\frac{4}{5}=1\frac{12}{15}$$

$$2\frac{7}{10}+1\frac{1}{3}-1\frac{4}{5}=2\frac{21}{30}+\frac{14}{30}=2\frac{7}{30}=\frac{67}{30}$$

$$1\frac{53}{67}=\frac{120}{67}$$

$$\frac{67}{30}\cdot \frac{120}{67}=4$$

е) $$1\frac{1}{16}:\left(7\frac{2}{5}-12\frac{3}{8}+37{,}525\right)$$

$$1\frac{1}{16}=\frac{17}{16},\quad 7\frac{2}{5}=7{,}4,\quad 12\frac{3}{8}=12{,}375$$

$$7{,}4-12{,}375+37{,}525=7{,}4+25{,}15=32{,}55=\frac{3255}{100}=\frac{651}{20}$$

$$\frac{17}{16}:\frac{651}{20}=\frac{17}{16}\cdot \frac{20}{651}=\frac{85}{2604}$$

ж) $$\left(\frac{3}{7}+0{,}7-\frac{1}{10}\right)\cdot 5\frac{5}{6}$$

$$0{,}7=\frac{7}{10},\quad 5\frac{5}{6}=\frac{35}{6}$$

$$\frac{3}{7}+\frac{7}{10}-\frac{1}{10}=\frac{3}{7}+\frac{6}{10}=\frac{3}{7}+\frac{3}{5}=\frac{15}{35}+\frac{21}{35}=\frac{36}{35}$$

$$\frac{36}{35}\cdot \frac{35}{6}=6$$

з) $$\frac{\left(1\frac{7}{25}+12\frac{3}{5}-8{,}9\right)\cdot 0{,}5}{0{,}2388:796}$$

$$1\frac{7}{25}=1{,}28,\quad 12\frac{3}{5}=12{,}6$$

$$1{,}28+12{,}6-8{,}9=4{,}98$$

$$4{,}98\cdot 0{,}5=2{,}49$$

$$0{,}2388:796=0{,}0003$$

$$2{,}49:0{,}0003=8300$$

Ответ

а) $$-4{,}6$$; б) $$-1\frac{131}{180}$$; в) $$-5{,}12$$; г) $$-4\frac{44}{103}$$; д) $$4$$; е) $$\frac{85}{2604}$$; ж) $$6$$; з) $$8300$$.